XFEM in LS-DYNA
Hello,
Can anyone help me with some examples of XFEM implementation in LS-DYNA? Also, is XFEM in LS-DYNA currently applicable with shell elements only?
Thank you,
Prathyush
Hello,
Can anyone help me with some examples of XFEM implementation in LS-DYNA? Also, is XFEM in LS-DYNA currently applicable with shell elements only?
Thank you,
Prathyush
Hello eveybody,
I am confused in using numerical schemes: What can convergence of a numerical scheme tell us and what not??? lets assume that a numerical scheme does converge to "A result" or "A number", but how could we be sure that the scheme has actually converged to the "RIGHT solution" and not a WRONG one??
Any input is appreciated!
Setareh
Hi,
I have a bicrystal with 2 material orientations in Euler Angles. How do I assign them to my Abaqus Input file? I am using Dr Huang's code for CP. After going through several forums, I understood that I have to create a card with *ORIENTATION entry.
This is what I am trying to do:
http://imechanica.org/node/2909
Its not quite clear to me. Could anyone please please simplify and explain how I could do the same? Thanks a lot!
Hello all:
I am confused about how to transform Green–Lagrange strain defined using curvilinear coordinate to local Cartesian coordinate.
I wonder how important the initial set up for a Smoothed Particle Hydrodynamics simulation is. Is the initial particle distribution somehow significant for the final result? How to control particle density and distribution along problem domain? What are the important factors inherent to the initial set up? Having control over the initial set up is going against the philosophy of this method?
Dear all,
I am a Ph.D student. I am trying to calculate the value of the j-integral for a 3D penny shaped crack embeddee in a continuum linear elastic solid using ABAQUS.
the first difficulty that I have met is that j-integral values are negative forr some nodes along the crack front.
I am pretty sure that the value of the normal to the crack front that I have used is correct.
Do you know some other reason for that?
You can see two sliders. I apply force using one slider to another slider. Best part is one slider move little bit
and helps second slider
to slide 6 times length at 70 % force.
For More information please visit http://mechanicalresearch.info/
Energy Used to move first slider=force*distance
=100N*0.05m
=5Nm
Energy Get on Other Slider= Force*Distance
=Force applied by first slider*cos(45`)*distance
=100*0.7*0.25
=17.5