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how can the plastic strain be greater than unity?

Submitted by student on

Does anyone know how can the plastic strain be greater than unity? Such as in the benchmark manual 3.2.10 Indentation of a crushable foam plate: 

*CRUSHABLE FOAM HARDENING

 0.2000E6, 0.0000

 0.2577E6, 0.0094

 0.2760E6, 0.0258

 0.3053E6, 0.0452

 0.3267E6, 0.0655

 0.3623E6, 0.1084

 0.3891E6, 0.1540

 0.4250E6, 0.2405

 0.4568E6, 0.3812

 0.4738E6, 0.4600

 0.5170E6, 0.6391

 0.5862E6, 0.8570

 0.6503E6, 0.9857

 0.7470E6, 1.1324

 0.9820E6, 1.2965

 1.4702E6, 1.4808

 2.7262E6, 1.6609

 5.3911E6, 1.9000

 

As I Know that the formula for True strain is 

True Strain = ln(1+nominal strain)

and if we consider a compression process then nominal strain should not be greater than 1 and thus max true strain will be 

True Strain = ln(1+1)=ln(2)= 0.69

I know I am confusing somethings here, Kindly correct me

Your final equation is correct for a tensile nominal strain of 1. If you had a compressive nominal strain of -0.5 your equation would be

True Strain = ln(1-0.5) = -0.69

If we take the example to the extreme of compressing the material to 1/10th of its original length

True Strain = ln(0.1) = -2.30

Or to 10x the original length

True Strain = ln(10.0) = 2.30

That's how you get logarithmic strains with magnitudes greater than unity.

Fri, 09/11/2015 - 08:57 Permalink