iMechanica - Material Properties on Different Elements with Common Node - Comments

Hi, Thanks for the

shrimad — Fri, 05 Feb 2010 18:38:37 -0500

Hi,

Thanks for the reply. That clears it up. I was thinking about the same thing, but wasn't sure.

However, let's say the nodes are not coincident and are being used by both the bodies (the common node). Now, if that node is constrained fully as a rigid node (all disps = 0), in that case there will be no interdependence as the stiffnesses because of the constraint will not be in effect for both the bodies. Am I thinking right?

Shriram

In most codes, if two

PerformEngineering — Sun, 31 Jan 2010 15:55:22 -0500

In most codes, if two bodies are connected at a common node, the two bodies will act as if they are connected. If you want the two bodies to be disconnected, you will need to create two coincident nodes, so that each node is only used by one body. As long as there is nothing connecting the two coincident nodes, they will act independently. Of course, you'll have to worry about the physically impossible situation of the bodies interfering with each other.

Material Properties on Different Elements with Common Node

shrimad — Thu, 28 Jan 2010 17:35:16 -0500

Hi,

I am having a conceptual doubt regarding the following case. Any suggestions are appreciated. We are here assuming linear elastic material.

Let's say I have two bodies with different properties, and they share a common node (as in the attachment). However, I want to perform an analysis without any coupling or contact phenomena. Let's say thermal expansion of the bodies.So while doing the FEA analysis, I can assign the material properties in the element stiffness according to the body elements and solve.

Would that be equal to solving the same problem without having the node in common or the common node affects the net behaviour of both the bodies? There is no constraint at the common node.

Thanks,

Shriram